The time experienced by the Earth-bound observer ($t$) is related to the muon’s proper time ($t_0$) by the Lorentz factor ($\gamma$):
$$t = \gamma t_0$$
where $\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}$
* The muon’s proper time ($t_0$) is the time measured in the muon’s rest frame (the time it “experiences”).
* Because of time dilation, the muon’s half-life appears longer to an observer on Earth, allowing it to travel further before decaying.
* For example, if $\gamma = 15$, the muons average lifetime is now \$15 \times 2.2 \times 10^{-6} = 33 \mu s$ meaning muons can travel \$3 \times 10^8 \times 33 \times 10^{-6} = 9900m$
The length observed by the muon ($L$) is related to the proper length ($L_0$) by:
$$L = \frac{L_0}{\gamma}$$
where $L_0$ is the proper length (the distance measured in the Earth’s rest frame).
* Therefore, the muon perceives the distance it needs to travel as significantly shorter, making it more likely to reach the surface before decaying.
KEY TAKEAWAY: The detection of muons at the Earth’s surface is strong evidence for both time dilation and length contraction predicted by special relativity.
The relativistic mass ($m$) is related to the rest mass ($m_0$) by:
$$m = \gamma m_0$$
This means that as particles approach the speed of light, they become increasingly difficult to accelerate further, requiring significantly more energy.
The total energy of a particle is given by:
$$E_{tot} = \gamma mc^2 = E_k + E_0$$
where $E_k$ is the kinetic energy and $E_0 = mc^2$ is the rest energy.
* The kinetic energy can be calculated as:
$$E_k = (\gamma - 1)mc^2$$
Particle accelerators must be designed to provide enough energy to create new particles according to Einstein’s mass-energy equivalence ($E=mc^2$).
EXAM TIP: Problems involving particle accelerators often require calculating relativistic mass, energy, or the required magnetic field strength to maintain a particle’s circular path.
The satellites’ orbital velocity ($v \approx 3.9 km/s$) causes a time dilation effect.
$$t = \gamma t_0$$
The time dilation effect is small but significant, about 7 microseconds per day.
* This means that without correction, GPS would be off by a few kilometers each day.
| Effect | Special Relativity | General Relativity | Combined Effect |
|---|---|---|---|
| Cause | Satellites’ orbital velocity | Satellites’ altitude (weaker gravity) | N/A |
| Time Difference | ~7 microseconds/day (time dilation on satellite) | ~45 microseconds/day (time faster on satellite) | ~38 microseconds/day (time faster on satellite) |
| Correction Applied | Yes | Yes | N/A |
COMMON MISTAKE: Students often forget to consider both special and general relativistic effects when discussing GPS. Remember that both contribute to the overall time difference.
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