In VCE Specialist Mathematics, vectors are fundamental tools used to represent quantities that possess both size and orientation. This distinguishes them from scalars, which only have magnitude.
A scalar is a quantity that is fully described by its magnitude (size) and an appropriate unit. Examples include mass, time, distance, and speed.
A vector is a quantity that has both magnitude and direction. Examples include displacement, velocity, acceleration, and force.
STUDY HINT: Always use the tilde notation ($\tilde{v}$) in your SACs and Exams. VCAA assessors require clear distinction between scalar variables and vector variables.
Vectors are most commonly expressed in terms of standard unit vectors representing the axes of the Cartesian coordinate system.
A vector $\tilde{u}$ in 2D can be resolved into horizontal and vertical components:
$$\tilde{u} = x\tilde{i} + y\tilde{j}$$
* $\tilde{i}$: Unit vector in the positive direction of the $x$-axis.
* $\tilde{j}$: Unit vector in the positive direction of the $y$-axis.
* This can also be written as a column vector: $\begin{bmatrix} x \ y \end{bmatrix}$.
A vector $\tilde{u}$ in 3D adds a depth component:
$$\tilde{u} = x\tilde{i} + y\tilde{j} + z\tilde{k}$$
* $\tilde{k}$: Unit vector in the positive direction of the $z$-axis.
* This can also be written as a column vector: $\begin{bmatrix} x \ y \ z \end{bmatrix}$.
| Property | 2D Vector ($x\tilde{i} + y\tilde{j}$) | 3D Vector ($x\tilde{i} + y\tilde{j} + z\tilde{k}$) |
|---|---|---|
| Components | Two ($x, y$) | Three ($x, y, z$) |
| Basis Vectors | $\tilde{i}, \tilde{j}$ | $\tilde{i}, \tilde{j}, \tilde{k}$ |
| Visualisation | A plane | 3D Space |
VCAA FOCUS: Ensure you can switch fluently between component form ($x\tilde{i} + y\tilde{j} + z\tilde{k}$) and column vector form, as both appear frequently in exam questions.
The magnitude (or length) of a vector is a scalar quantity denoted by $|\tilde{v}|$ or $|\vec{AB}|$. It is calculated using Pythagoras’ Theorem.
COMMON MISTAKE: A common error is forgetting to square negative components correctly. Remember that $(-3)^2 = 9$. The magnitude of $\tilde{v} = -3\tilde{i} + 4\tilde{j}$ is $\sqrt{(-3)^2 + 4^2} = 5$, not $\sqrt{-9 + 16}$.
A unit vector is a vector with a magnitude of exactly 1.
To find a unit vector $\hat{v}$ (pronounced “v-hat”) that points in the same direction as a non-zero vector $\tilde{v}$, divide the vector by its own magnitude:
$$\hat{v} = \frac{1}{|\tilde{v}|}\tilde{v}$$
In the Cartesian system, the basis vectors are defined as:
* $\tilde{i} = \begin{bmatrix} 1 \ 0 \ 0 \end{bmatrix}$, $|\tilde{i}| = 1$
* $\tilde{j} = \begin{bmatrix} 0 \ 1 \ 0 \end{bmatrix}$, $|\tilde{j}| = 1$
* $\tilde{k} = \begin{bmatrix} 0 \ 0 \ 1 \end{bmatrix}$, $|\tilde{k}| = 1$
KEY TAKEAWAY: A unit vector represents direction only. If you need a vector of a specific length $L$ in the direction of $\tilde{v}$, the formula is $L\hat{v}$.
Two vectors are equal if and only if they have the same magnitude and the same direction. In component form, $\tilde{u} = \tilde{v}$ if $x_1 = x_2$, $y_1 = y_2$, and $z_1 = z_2$.
Multiplying a vector $\tilde{v}$ by a scalar $k$:
* If $k > 0$, the direction remains the same, but the magnitude is scaled by $k$.
* If $k < 0$, the direction is reversed, and the magnitude is scaled by $|k|$.
* The vector $-\tilde{v}$ has the same magnitude as $\tilde{v}$ but the opposite direction.
Two non-zero vectors $\tilde{u}$ and $\tilde{v}$ are parallel if one is a scalar multiple of the other:
$$\tilde{u} = k\tilde{v} \text{ for some } k \in \mathbb{R} \setminus {0}$$
EXAM TIP: To prove three points $A, B,$ and $C$ are collinear (lie on the same straight line), show that the vectors $\vec{AB}$ and $\vec{BC}$ are parallel (i.e., $\vec{AB} = k\vec{BC}$) and share a common point $B$.