In VCE Specialist Mathematics, a vector is defined as a quantity that possesses both magnitude and direction. This distinguishes it from a scalar, which has magnitude only (e.g., mass, time, or speed).
Vectors can be represented geometrically as directed line segments or algebraically using components.
KEY TAKEAWAY: A vector is not fixed in space; two vectors are considered equal if they have the same magnitude and the same direction, regardless of their starting points.
Vector addition can be understood both geometrically and algebraically.
To add vectors algebraically, add their corresponding components:
If \(\mathbf{a} = a_1\mathbf{i} + a_2\mathbf{j} + a_3\mathbf{k}\) and \(\mathbf{b} = b_1\mathbf{i} + b_2\mathbf{j} + b_3\mathbf{k}\), then:
\$\(\mathbf{a} + \mathbf{b} = (a_1 + b_1)\mathbf{i} + (a_2 + b_2)\mathbf{j} + (a_3 + b_3)\mathbf{k}\)\$
EXAM TIP: When a question involves a closed geometric figure (like a triangle or hexagon), the sum of vectors forming a closed loop returning to the start point is always the zero vector \(\mathbf{0}\).
Subtraction is defined as the addition of a negative vector. The negative vector \(-\mathbf{b}\) has the same magnitude as \(\mathbf{b}\) but points in the opposite direction.
If \(\mathbf{a}\) and \(\mathbf{b}\) are drawn from the same origin \(O\), such that \(\vec{OA} = \mathbf{a}\) and \(\vec{OB} = \mathbf{b}\), then the vector \(\mathbf{a} - \mathbf{b}\) is the vector \(\vec{BA}\) (the vector pointing from the head of \(\mathbf{b}\) to the head of \(\mathbf{a}\)).
Subtract corresponding components:
\$\(\mathbf{a} - \mathbf{b} = (a_1 - b_1)\mathbf{i} + (a_2 - b_2)\mathbf{j} + (a_3 - b_3)\mathbf{k}\)\$
COMMON MISTAKE: Students often reverse the direction of the subtraction vector. Remember: \(\mathbf{a} - \mathbf{b}\) points towards \(\mathbf{a}\). A helpful mnemonic is “Final minus Initial” (\(\vec{BA} = \text{position } A - \text{position } B\)).
Scalar multiplication involves multiplying a vector \(\mathbf{a}\) by a real number \(k\) (a scalar).
Two non-zero vectors \(\mathbf{a}\) and \(\mathbf{b}\) are parallel if and only if one is a scalar multiple of the other:
\$\(\mathbf{a} \parallel \mathbf{b} \iff \mathbf{a} = k\mathbf{b} \text{ for some } k \in \mathbb{R} \setminus \{0\}\)\$
A unit vector is a vector with a magnitude of 1. To find a unit vector \(\hat{\mathbf{a}}\) in the direction of \(\mathbf{a}\):
\$\(\hat{\mathbf{a}} = \frac{1}{|\mathbf{a}|}\mathbf{a}\)\$
where \(|\mathbf{a}| = \sqrt{a_1^2 + a_2^2 + a_3^2}\).
STUDY HINT: Scalar multiplication is distributive over vector addition: \(k(\mathbf{a} + \mathbf{b}) = k\mathbf{a} + k\mathbf{b}\). This is a fundamental tool for simplifying algebraic vector expressions.
A vector \(\mathbf{r}\) is a linear combination of vectors \(\mathbf{v}_1, \mathbf{v}_2, \dots, \mathbf{v}_n\) if it can be expressed in the form:
\$\(\mathbf{r} = c_1\mathbf{v}_1 + c_2\mathbf{v}_2 + \dots + c_n\mathbf{v}_n\)\$
where \(c_1, c_2, \dots, c_n\) are scalar coefficients.
If a vector \(\mathbf{p}\) is a linear combination of \(\mathbf{a}\) and \(\mathbf{b}\), we set up the equation:
\$\(\mathbf{p} = m\mathbf{a} + n\mathbf{b}\)\$
By equating the \(\mathbf{i}, \mathbf{j}\) and \(\mathbf{k}\) components, we create a system of simultaneous equations to solve for the scalars \(m\) and \(n\).
VCAA FOCUS: Many exam questions require you to prove that three points \(A, B,\) and \(C\) are collinear. This is achieved by showing that the vectors \(\vec{AB}\) and \(\vec{BC}\) (or \(\vec{AC}\)) are parallel (scalar multiples) and share a common point \(B\).
| Operation | Algebraic Formula (for \(\mathbf{i}, \mathbf{j}, \mathbf{k}\)) | Geometric Meaning |
|---|---|---|
| Addition | \((a_1+b_1)\mathbf{i} + (a_2+b_2)\mathbf{j} + (a_3+b_3)\mathbf{k}\) | Tip-to-tail resultant |
| Subtraction | \((a_1-b_1)\mathbf{i} + (a_2-b_2)\mathbf{j} + (a_3-b_3)\mathbf{k}\) | Vector between two points |
| Scalar Mult. | \((ka_1)\mathbf{i} + (ka_2)\mathbf{j} + (ka_3)\mathbf{k}\) | Scaling/Reversing direction |
| Magnitude | \$ | \mathbf{a} |
REMEMBER: The zero vector \(\mathbf{0} = 0\mathbf{i} + 0\mathbf{j} + 0\mathbf{k}\) is the only vector with a magnitude of 0 and no defined direction. It is essential for solving vector equations where all terms cancel out.