In VCE Specialist Mathematics, curves can be represented in forms other than the standard Cartesian equation $y = f(x)$. Parametric and polar forms allow for the description of complex paths, such as circles, ellipses, and spirals, which may not be functions in the Cartesian plane.
A curve is defined parametrically if both the $x$ and $y$ coordinates are expressed as functions of a third variable, $t$, known as the parameter.
$$x = f(t), \quad y = g(t) \quad \text{for } t \in [a, b]$$
To convert parametric equations to a Cartesian equation, we eliminate $t$. Common methods include:
Given $x = 1 + 3\cos(t)$ and $y = -2 + 2\sin(t)$ for $t \in [0, 2\pi]$:
1. Rearrange for the trig terms: $\cos(t) = \frac{x-1}{3}$ and $\sin(t) = \frac{y+2}{2}$.
2. Substitute into $\cos^2(t) + \sin^2(t) = 1$:
$$\left(\frac{x-1}{3}\right)^2 + \left(\frac{y+2}{2}\right)^2 = 1 \implies \frac{(x-1)^2}{9} + \frac{(y+2)^2}{4} = 1$$
This is the Cartesian equation of an ellipse centered at $(1, -2)$.
EXAM TIP: When converting to Cartesian form, always check if the domain of the parameter $t$ restricts the $x$ or $y$ values. For example, if $x = \cos^2(t)$, then $x$ must be in the interval $[0, 1]$.
The polar coordinate system represents a point $P$ in the plane by its distance from the origin ($r$) and the angle ($\theta$) it makes with the positive $x$-axis.
The relationship between Cartesian coordinates $(x, y)$ and polar coordinates $(r, \theta)$ is defined by:
| From Polar to Cartesian | From Cartesian to Polar |
|---|---|
| $x = r\cos(\theta)$ | $r^2 = x^2 + y^2$ |
| $y = r\sin(\theta)$ | $\tan(\theta) = \frac{y}{x}$ |
KEY TAKEAWAY: A single point in the plane has infinitely many polar representations because $\theta$ is periodic (e.g., $(r, \theta)$ is the same as $(r, \theta + 2\pi)$). By convention, we often use $r \ge 0$ and $\theta \in (-\pi, \pi]$ or $[0, 2\pi)$.
A polar equation is typically given in the form $r = f(\theta)$.
COMMON MISTAKE: When converting $r = f(\theta)$ to Cartesian form, students often forget to square both sides correctly or fail to recognize that $r = \sqrt{x^2+y^2}$ only if $r \ge 0$.
When sketching parametric or polar curves, consider:
To find the gradient $\frac{dy}{dx}$ of a curve defined parametrically:
$$\frac{dy}{dx} = \frac{dy/dt}{dx/dt}$$
This is essential for finding stationary points or the equations of tangents to parametric curves.
VCAA FOCUS: VCAA frequently examines the conversion of an ellipse or hyperbola from parametric to Cartesian form and vice versa. Be comfortable with the identity $\sec^2(t) = 1 + \tan^2(t)$ for hyperbolas.