KEY TAKEAWAY: Satellites are objects orbiting a larger mass, and in VCE Physics, we assume their orbits are uniform and circular.
The equation for gravitational force is:
$$F_g = G \frac{Mm}{r^2}$$
where:
* $F_g$ is the gravitational force
* $G$ is the gravitational constant (\$6.674 \times 10^{-11} \, Nm^2/kg^2$)
* $M$ is the mass of the larger object (e.g., Earth)
* $m$ is the mass of the satellite
* $r$ is the distance between the centers of the two objects (orbital radius)
The equation for centripetal force is:
$$F_c = \frac{mv^2}{r}$$
where:
* $F_c$ is the centripetal force
* $m$ is the mass of the satellite
* $v$ is the orbital speed of the satellite
* $r$ is the orbital radius
Since the gravitational force provides the centripetal force, we can equate the two:
$$G \frac{Mm}{r^2} = \frac{mv^2}{r}$$
We can simplify this equation to solve for the orbital speed:
$$v = \sqrt{\frac{GM}{r}}$$
APPLICATION: The gravitational force between a satellite and the Earth acts as the centripetal force, keeping the satellite in orbit.
The orbital speed ($v$) is the speed at which the satellite moves along its circular path. As derived above:
$$v = \sqrt{\frac{GM}{r}}$$
The orbital period ($T$) is the time it takes for the satellite to complete one orbit. It is related to the orbital speed and radius by:
$$v = \frac{2\pi r}{T}$$
Combining these equations, we can find the orbital period:
$$T = \frac{2\pi r}{v} = \frac{2\pi r}{\sqrt{\frac{GM}{r}}} = 2\pi \sqrt{\frac{r^3}{GM}}$$
This equation shows that the orbital period depends only on the orbital radius and the mass of the central object.
EXAM TIP: Be prepared to calculate the orbital speed or period given the orbital radius and the mass of the central object.
The magnitude of the centripetal acceleration is:
$$a = \frac{v^2}{r} = \frac{4\pi^2 r}{T^2}$$
Since the gravitational force provides the centripetal force, the centripetal acceleration is equal to the gravitational field strength at the satellite’s location:
$$a = \frac{GM}{r^2}$$
VCAA FOCUS: VCAA often tests your understanding of the relationship between gravitational force, centripetal force, orbital speed, and orbital period.
COMMON MISTAKE: Astronauts are not in “zero gravity.” They are still affected by Earth’s gravity. They feel weightless because they are in free fall and do not experience a normal force.
| Force | Definition | Direction | Present for Satellites? |
|---|---|---|---|
| Gravitational | Force of attraction between two masses. | Towards the center of the larger mass (e.g., Earth). | Yes |
| Normal | Force exerted by a surface on an object in contact with it. | Perpendicular to the surface. | No |
STUDY HINT: Create a table comparing and contrasting gravitational and normal forces to solidify your understanding.
REMEMBER: The concepts of gravitational force and centripetal force are fundamental to understanding satellite motion.
Free exam-style questions on Forces on satellites with instant AI feedback.
A communication satellite of mass 500 kg orbits the Earth in a circular orbit at an altitude where the gravitational field strength is 2.0 N…
A satellite is in a stable, circular orbit around Earth. Describe the relationship between the force due to gravity acting on the satellite…
A new space elevator is proposed, extending from Earth's surface to a geostationary orbit. An astronaut ascends the elevator. Discuss how th…
A satellite is orbiting Earth in a circular orbit. An astronaut inside the satellite is standing on a scale. Which of the following statemen…
A satellite is in a stable, circular orbit around a planet. Which of the following statements best describes the normal force acting on an o…
A satellite is in a stable circular orbit around a planet. Which of the following statements best describes the normal force experienced by…
A 600 kg satellite is in a stable circular orbit around Earth at an altitude of 2000 km. An astronaut inside the satellite is conducting an…