An equation for the variable $x$ in which all the coefficients of $x$, including the constants, are pronumerals is known as a literal equation.
Literal equations are solved by isolating the variable (usually $x$) in terms of other pronumerals. The solution will be an expression involving these pronumerals, rather than a numerical value.
Example:
Solve for $x$ in the literal equation $ax + b = c$.
$$ax + b = c$$
$$ax = c - b$$
$$x = \frac{c - b}{a}$$ (assuming $a \neq 0$)
The methods for solving linear literal equations are the same as those used for solving standard linear equations with numerical coefficients. The goal is to isolate the variable on one side of the equation.
Steps:
Example:
Solve for $x$ in the equation $mx + n = nx - m$.
$$mx + n = nx - m$$
$$mx - nx = -m - n$$
$$x(m - n) = -(m + n)$$
$$x = -\frac{m + n}{m - n}$$ (assuming $m \neq n$)
Simultaneous literal equations involve two or more equations with two or more variables, where the coefficients are pronumerals. These can be solved using substitution or elimination, just like standard simultaneous equations.
Methods
Example:
Solve the following simultaneous equations for $x$ and $y$:
$$ax - y = c$$
$$x + by = d$$
Multiply the first equation by $b$:
$$abx - by = bc$$
2. Add this to the second equation:
$$abx - by + x + by = bc + d$$
$$x(ab + 1) = bc + d$$
$$x = \frac{bc + d}{ab + 1}$$
Substitute the value of $x$ into the second original equation:
$$\frac{bc + d}{ab + 1} + by = d$$
$$by = d - \frac{bc + d}{ab + 1}$$
$$by = \frac{d(ab + 1) - (bc + d)}{ab + 1}$$
$$by = \frac{abd + d - bc - d}{ab + 1}$$
$$by = \frac{abd - bc}{ab + 1}$$
$$y = \frac{abd - bc}{b(ab + 1)}$$
$$y = \frac{ad - c}{ab + 1}$$
Non-linear literal equations can include quadratic, cubic, or other higher-order terms. Solving these equations may involve factoring, using the quadratic formula, or other algebraic techniques.
Example:
Solve for $x$ in the equation $x^2 + kx + k = 0$.
Using the quadratic formula:
$$x = \frac{-k \pm \sqrt{k^2 - 4(1)(k)}}{2(1)}$$
$$x = \frac{-k \pm \sqrt{k^2 - 4k}}{2}$$
A real solution exists only for $k^2 - 4k \geq 0$, which means $k \geq 4$ or $k \leq 0$.
Equations involving a single parameter require you to express the solution in terms of that parameter. This often involves rearranging the equation and considering any restrictions on the parameter.
Example:
Solve for $x$: $a(x + b)^3 = c$
$$(x + b)^3 = \frac{c}{a}$$
$$x + b = \sqrt[3]{\frac{c}{a}}$$
$$x = \sqrt[3]{\frac{c}{a}} - b$$
Example:
Solve for $x$: $x^4 = c$, where $c > 0$
$$x = \pm \sqrt[4]{c}$$
Note: Care must be taken with even powers; for example, $x^2 = 2$ is equivalent to $x = \pm \sqrt{2}$.
Free exam-style questions on Literal and General Equations with instant AI feedback.
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