This section covers transformations of functions of the form $y = f(x)$ to $y = Af(n(x+b)) + c$, where $A, n, b,$ and $c$ are real numbers, and $A, n
eq 0$. We’ll also explore the inverse transformation.
This equation combines several transformations. Let’s break down each parameter:
A: Vertical dilation (stretch/compression) and/or reflection in the x-axis.
n: Horizontal dilation (stretch/compression) and/or reflection in the y-axis.
b: Horizontal translation.
c: Vertical translation.
It is crucial to apply transformations in the correct order. A recommended order is:
We can represent the transformation using mapping notation:
$(x, y) \rightarrow (\frac{x}{n} - b, Ay + c)$
This notation shows how a point $(x, y)$ on the original graph $y = f(x)$ is mapped to a new point $(\frac{x}{n} - b, Ay + c)$ on the transformed graph $y = Af(n(x+b)) + c$.
To find the inverse transformation, we need to reverse the process. If the original transformation is:
$y = Af(n(x+b)) + c$
Then the inverse transformation can be found as follows:
Finally, swap $x$ and $y$ to express the inverse function in terms of x:
$y = \frac{1}{n}f^{-1}(\frac{x-c}{A}) - b$
Or, using mapping notation, the inverse transformation is:
$(x, y) \rightarrow (\frac{x - c}{A}, ny + b)$
| Function | Transformation | Effect |
|---|---|---|
| $y = x^2$ | $y = -(x+2)^2 - 1$ | Reflected in x-axis, translated 2 units left, 1 unit down |
| $y = \sqrt{x}$ | $y = 2\sqrt{x-3}$ | Vertical stretch by 2, translated 3 units right |
| $y = \frac{1}{x}$ | $y = \frac{3}{2x} + 4$ | Vertical stretch by 3, horizontal compression by $\frac{1}{2}$, translated 4 units up |
| $y = e^x$ | $y = e^{-x} - 2$ | Reflected in y-axis, translated 2 units down |
| $y = \sin(x)$ | $y = 3\sin(2x)$ | Vertical stretch by 3, horizontal compression by $\frac{1}{2}$ |
Free exam-style questions on Function Transformations with instant AI feedback.
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