Differentiation for Graph Sketching
Key Features of Graphs
Differentiation is a powerful tool for analyzing and sketching graphs of functions. By finding the first and second derivatives, we can identify key features such as:
- Stationary Points: Points where the gradient of the function is zero ($f’(x) = 0$). These can be local maxima, local minima, or stationary points of inflection.
- Points of Inflection: Points where the concavity of the function changes. These occur where the second derivative is zero or undefined ($f’‘(x) = 0$).
- Intervals of Increasing and Decreasing: Intervals where the function is strictly increasing ($f’(x) > 0$) or strictly decreasing ($f’(x) < 0$).
KEY TAKEAWAY: Differentiation allows us to move beyond plotting points and truly understand the behavior of a function.
Stationary Points
Definition
A stationary point of a function $f(x)$ is a point where the derivative $f’(x) = 0$. At these points, the tangent to the curve is horizontal.
Types of Stationary Points
- Local Maximum: A point where the function reaches a maximum value within a small interval. To the left of the maximum, the function is increasing ($f’(x) > 0$), and to the right, it is decreasing ($f’(x) < 0$).
- Local Minimum: A point where the function reaches a minimum value within a small interval. To the left of the minimum, the function is decreasing ($f’(x) < 0$), and to the right, it is increasing ($f’(x) > 0$).
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Stationary Point of Inflection: A point where the gradient is zero, but the function does not change direction (i.e., it doesn’t go from increasing to decreasing or vice-versa). The concavity changes at this point.
- Gradient positive to the left and right: gradient + 0 +
- Gradient negative to the left and right: gradient - 0 -
Determining the Nature of Stationary Points
First Derivative Test
- Find the $x$-values where $f’(x) = 0$. These are the $x$-coordinates of the stationary points.
- Choose test values of $x$ slightly to the left and right of each stationary point.
- Evaluate $f’(x)$ at these test values.
- Determine the nature of the stationary point based on the sign change of $f’(x)$:
- Positive to Negative: Local Maximum
- Negative to Positive: Local Minimum
- Positive to Positive or Negative to Negative: Stationary Point of Inflection
Second Derivative Test
- Find the second derivative, $f’‘(x)$.
- Evaluate $f’‘(x)$ at each stationary point (where $f’(x) = 0$).
- Determine the nature of the stationary point based on the value of $f’‘(x)$:
- $f’‘(x) > 0$: Local Minimum
- $f’‘(x) < 0$: Local Maximum
- $f’‘(x) = 0$: The test is inconclusive; use the first derivative test.
EXAM TIP: The second derivative test is often easier to apply, but remember it’s inconclusive when $f’‘(x) = 0$.
Points of Inflection
Definition
A point of inflection is a point on a curve where the concavity changes. This means the curve changes from being concave up to concave down, or vice versa.
Finding Points of Inflection
- Find the second derivative, $f’‘(x)$.
- Solve $f’‘(x) = 0$ for $x$. These are potential points of inflection.
- Check that the concavity changes at these points. This can be done by:
- Evaluating $f’‘(x)$ on either side of the potential point of inflection. If the sign of $f’‘(x)$ changes, then it is a point of inflection.
- Checking that $f’‘’(x) \neq 0$ at the point. (If the third derivative exists and is non-zero, it’s a point of inflection.)
Concavity
- Concave Up: The curve is shaped like a cup opening upwards. $f’‘(x) > 0$.
- Concave Down: The curve is shaped like a cup opening downwards. $f’‘(x) < 0$.
COMMON MISTAKE: For a stationary point of inflection, both $f’(x) = 0$ and $f’‘(x) = 0$. However, not all points where $f’‘(x) = 0$ are stationary points of inflection.
Intervals of Increasing and Decreasing Functions
Increasing Function
A function $f(x)$ is strictly increasing on an interval if $f’(x) > 0$ for all $x$ in that interval. As $x$ increases, $y$ also increases.
Decreasing Function
A function $f(x)$ is strictly decreasing on an interval if $f’(x) < 0$ for all $x$ in that interval. As $x$ increases, $y$ decreases.
Finding Intervals of Increasing and Decreasing
- Find the first derivative, $f’(x)$.
- Find the critical points where $f’(x) = 0$ or $f’(x)$ is undefined. These points divide the domain into intervals.
- Choose a test value within each interval and evaluate $f’(x)$ at that value.
- Determine whether the function is increasing or decreasing in each interval based on the sign of $f’(x)$:
- $f’(x) > 0$: Increasing
- $f’(x) < 0$: Decreasing
STUDY HINT: Create a sign diagram for $f’(x)$ to visually represent the intervals of increasing and decreasing.
Graph Sketching
To sketch a graph of a function $f(x)$ using differentiation, follow these steps:
- Find the domain and range (if possible).
- Find the $x$ and $y$ intercepts.
- Find the stationary points and determine their nature (local max, local min, or stationary point of inflection).
- Find the points of inflection.
- Determine the intervals of increasing and decreasing.
- Determine the concavity of the function.
- Consider the end behavior of the function (as $x$ approaches positive and negative infinity).
- Sketch the graph, plotting all key points and ensuring the graph reflects the information gathered in the previous steps.
APPLICATION: Graph sketching is used in many real-world scenarios, such as modeling population growth, analyzing financial data, and designing engineering structures.
Example
Let’s sketch the graph of $f(x) = x^3 - 3x^2 + 2$.
- Domain: $R$
- y-intercept: $f(0) = 2$
- First derivative: $f’(x) = 3x^2 - 6x$
- Stationary points: $f’(x) = 0 \Rightarrow 3x(x - 2) = 0 \Rightarrow x = 0, 2$
- Second derivative: $f’‘(x) = 6x - 6$
- Nature of stationary points:
- $f’‘(0) = -6 < 0 \Rightarrow$ Local maximum at $(0, 2)$
- $f’‘(2) = 6 > 0 \Rightarrow$ Local minimum at $(2, -2)$
- Point of inflection: $f’‘(x) = 0 \Rightarrow 6x - 6 = 0 \Rightarrow x = 1$
- Intervals of increasing/decreasing:
- $x < 0$: $f’(x) > 0$ (increasing)
- \$0 < x < 2$: $f’(x) < 0$ (decreasing)
- $x > 2$: $f’(x) > 0$ (increasing)
- Concavity:
- $x < 1$: $f’‘(x) < 0$ (concave down)
- $x > 1$: $f’‘(x) > 0$ (concave up)
Using this information, you can accurately sketch the graph of $f(x)$.
VCAA FOCUS: Exam questions often require you to sketch graphs and identify key features. Practice sketching a variety of functions, including polynomials, trigonometric functions, and exponentials.