A continuous random variable is a variable whose value can take on any value within a given range or interval.
A probability density function (PDF), denoted by $f(x)$, is a function that describes the relative likelihood for a continuous random variable to take on a given value.
PDFs are constructed from non-negative functions of a real variable. To make a non-negative function a valid PDF, it must be scaled such that the total area under the curve is equal to 1. This often involves finding a constant $k$ such that $\int_{-\infty}^{\infty} k \cdot g(x) \, dx = 1$, where $g(x)$ is the original non-negative function.
KEY TAKEAWAY: A PDF must be non-negative and have a total area under the curve of 1.
A probability distribution for a continuous random variable is specified by its PDF, $f(x)$. This function allows us to calculate probabilities associated with the random variable.
The mean (or expected value) of a continuous random variable $X$ with PDF $f(x)$ is given by:
$$\mu = E(X) = \int_{-\infty}^{\infty} x \cdot f(x) \, dx$$
The variance of a continuous random variable $X$ with PDF $f(x)$ and mean $\mu$ is given by:
$$\sigma^2 = Var(X) = E[(X - \mu)^2] = \int_{-\infty}^{\infty} (x - \mu)^2 \cdot f(x) \, dx$$
A more convenient formula for calculation is:
$$\sigma^2 = E(X^2) - \mu^2 = \int_{-\infty}^{\infty} x^2 \cdot f(x) \, dx - \mu^2$$
The standard deviation is the square root of the variance:
$$\sigma = \sqrt{Var(X)}$$
EXAM TIP: Remember to use the correct formulas for mean and variance. Pay attention to the integration limits based on the PDF’s domain.
The standard normal distribution, denoted by $N(0, 1)$, is a normal distribution with a mean of 0 and a standard deviation of 1. Its PDF is given by:
$$f(z) = \frac{1}{\sqrt{2\pi}} e^{-\frac{z^2}{2}}$$
where $z$ is the standard normal variable.
A transformed normal distribution, denoted by $N(\mu, \sigma^2)$, is a normal distribution with a mean of $\mu$ and a variance of $\sigma^2$. Its PDF is given by:
$$f(x) = \frac{1}{\sigma\sqrt{2\pi}} e^{-\frac{(x - \mu)^2}{2\sigma^2}}$$
where $x$ is the random variable.
Any normal distribution $N(\mu, \sigma^2)$ can be transformed into the standard normal distribution $N(0, 1)$ by using the z-score formula:
$$z = \frac{x - \mu}{\sigma}$$
This allows us to use standard normal tables or calculators to find probabilities associated with any normal distribution.
REMEMBER: The standard normal distribution is a special case of the normal distribution with $\mu=0$ and $\sigma=1$.
For a normal distribution $N(\mu, \sigma^2)$:
For a general PDF, the effect of changing parameters depends on the specific function. However, common effects include:
VCAA FOCUS: VCAA often tests your understanding of how changing parameters affects the shape and position of a normal distribution.
The probability that a continuous random variable $X$ lies within an interval $(a, b)$ is given by the area under the PDF $f(x)$ between $a$ and $b$:
$$P(a < X < b) = \int_{a}^{b} f(x) \, dx$$
The cumulative distribution function (CDF), denoted by $F(x)$, gives the probability that the random variable $X$ is less than or equal to $x$:
$$F(x) = P(X \leq x) = \int_{-\infty}^{x} f(t) \, dt$$
Although the CDF is not required knowledge, it can be a useful tool. Then, $P(a < X < b) = F(b) - F(a)$.
The conditional probability of event A given event B is:
$$P(A|B) = \frac{P(A \cap B)}{P(B)}$$
For continuous random variables, this often involves finding the probability of $X$ being in a specific interval given that it is already in another interval. For example:
$$P(a < X < b | c < X < d) = \frac{P(a < X < b \cap c < X < d)}{P(c < X < d)}$$
Where $a < b$ and $c < d$. If the intervals overlap, adjust the intersection accordingly.
If $c < a < b < d$, then
$$P(a < X < b | c < X < d) = \frac{P(a < X < b)}{P(c < X < d)} = \frac{\int_{a}^{b} f(x) \, dx}{\int_{c}^{d} f(x) \, dx}$$
COMMON MISTAKE: When calculating conditional probabilities, make sure to correctly identify the intersection of the events and divide by the probability of the condition.
Calculators can be used to evaluate definite integrals and find probabilities associated with continuous random variables. Specifically, use the normal CDF function for normal distributions.
APPLICATION: Continuous random variables and their PDFs are used in a wide variety of fields, including engineering, finance, and physics, for modeling and analyzing data.
Free exam-style questions on Continuous Random Variables with instant AI feedback.
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