An Eulerian path traverses every edge exactly once (vertices may be revisited).
An Eulerian circuit is an Eulerian path that starts and ends at the same vertex.
| Type | Condition |
|---|---|
| Eulerian circuit exists | Every vertex has even degree |
| Eulerian path exists (not circuit) | Exactly two vertices have odd degree (start and end at those vertices) |
If more than two vertices have odd degree, no Eulerian path exists.
Graph with vertices A, B, C, D, E and edges A–B, A–C, B–C, B–D, C–D, C–E, D–E.
Degrees: $\deg(A)=2$, $\deg(B)=3$, $\deg(C)=4$, $\deg(D)=3$, $\deg(E)=2$.
Odd-degree vertices: B (3) and D (3). Exactly two — an Eulerian path exists from B to D (or D to B), but not a circuit.
A Hamiltonian path visits every vertex exactly once.
A Hamiltonian circuit visits every vertex exactly once and returns to the starting vertex.
| Eulerian | Hamiltonian | |
|---|---|---|
| Focus | Every edge used once | Every vertex visited once |
| Condition | Degree-based test | No simple test (must trial routes) |
A salesperson must visit 4 cities (A, B, C, D) and return to A. Connections exist: A–B, A–C, B–C, B–D, C–D.
Try: A → B → D → C → A. Check: visits A, B, D, C each once and returns to A. This is a valid Hamiltonian circuit.
REMEMBER: Eulerian = Edges (every edge once). Hamiltonian = Houses/stops (every vertex once). The first letter helps you remember.
EXAM TIP: VCAA questions often show a graph and ask you to identify or describe an Eulerian or Hamiltonian path/circuit. Draw and label the route clearly, listing vertices in order.